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import os
import pkg_resources
import sys
def caller_path(path, level=2):
""" Return an absolute path """
if not os.path.isabs(path):
module = caller_module(level+1)
prefix = package_path(module)
path = os.path.join(prefix, path)
return path
def caller_module(level=2):
module_globals = sys._getframe(level).f_globals
module_name = module_globals['__name__']
module = sys.modules[module_name]
return module
def package_name(pkg_or_module):
""" If this function is passed a module, return the dotted Python
package name of the package in which the module lives. If this
function is passed a package, return the dotted Python package
name of the package itself."""
if pkg_or_module is None:
return '__main___'
pkg_filename = pkg_or_module.__file__
pkg_name = pkg_or_module.__name__
splitted = os.path.split(pkg_filename)
if splitted[-1] in ('__init__.py', '__init__.pyc', '__init__.pyo'):
# it's a package
return pkg_name
return pkg_name.rsplit('.', 1)[0]
def caller_package(level=2, caller_module=caller_module):
# caller_module in arglist for tests
module = caller_module(level+1)
if '__init__.py' in getattr(module, '__file__', ''): # empty at >>>
# Module is a package
return module
# Go up one level to get package
package_name = module.__name__.rsplit('.', 1)[0]
return sys.modules[package_name]
def package_path(package):
# computing the abspath is actually kinda expensive so we memoize
# the result
prefix = getattr(package, '__bfg_abspath__', None)
if prefix is None:
prefix = pkg_resources.resource_filename(package.__name__, '')
# pkg_resources doesn't care whether we feed it a package
# name or a module name within the package, the result
# will be the same: a directory name to the package itself
try:
package.__bfg_abspath__ = prefix
except:
# this is only an optimization, ignore any error
pass
return prefix
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